一、 漏洞 CVE-2024-26616 基础信息
漏洞标题
btrfs: scrub: 在chunk长度不是64K对齐的情况下,避免使用后释放的情况
来源:AIGC 神龙大模型
漏洞描述信息
In the Linux kernel's Btrfs file system, there has been a vulnerability resolved. The issue involved the scrub process causing problems due to improper use-after-free situations. Here's a breakdown of the situation: 1. The converted filesystem had an unusual data chunk layout. 2. During scrubbing, a specific logical byte number was at the end of a chunk. 3. As part of the scrub process, btrfs_submit_bio() would split bio and call endio multiple times, causing issues due to incorrect use-after-free handling. To fix this issue, the following changes were implemented: 1. scrub_read_endio() was updated to only modify bits within its range. This prevented updating error bits outside of chunk boundaries. 2. scrub_submit_initial_read() was adjusted to read only the chunk's range. This ensured that reads beyond chunk boundaries did not occur. As a result of these fixes, the scrub process in Btrfs became more robust and less prone to use-after-free issues, ensuring better data integrity during scrubbing.
来源:AIGC 神龙大模型
CVSS信息
CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:N/A:H
来源:AIGC 神龙大模型
漏洞类别
释放后使用
来源:AIGC 神龙大模型
漏洞标题
btrfs: scrub: avoid use-after-free when chunk length is not 64K aligned
来源:美国国家漏洞数据库 NVD
漏洞描述信息
In the Linux kernel, the following vulnerability has been resolved: btrfs: scrub: avoid use-after-free when chunk length is not 64K aligned [BUG] There is a bug report that, on a ext4-converted btrfs, scrub leads to various problems, including: - "unable to find chunk map" errors BTRFS info (device vdb): scrub: started on devid 1 BTRFS critical (device vdb): unable to find chunk map for logical 2214744064 length 4096 BTRFS critical (device vdb): unable to find chunk map for logical 2214744064 length 45056 This would lead to unrepariable errors. - Use-after-free KASAN reports: ================================================================== BUG: KASAN: slab-use-after-free in __blk_rq_map_sg+0x18f/0x7c0 Read of size 8 at addr ffff8881013c9040 by task btrfs/909 CPU: 0 PID: 909 Comm: btrfs Not tainted 6.7.0-x64v3-dbg #11 c50636e9419a8354555555245df535e380563b2b Hardware name: QEMU Standard PC (Q35 + ICH9, 2009), BIOS 2023.11-2 12/24/2023 Call Trace: <TASK> dump_stack_lvl+0x43/0x60 print_report+0xcf/0x640 kasan_report+0xa6/0xd0 __blk_rq_map_sg+0x18f/0x7c0 virtblk_prep_rq.isra.0+0x215/0x6a0 [virtio_blk 19a65eeee9ae6fcf02edfad39bb9ddee07dcdaff] virtio_queue_rqs+0xc4/0x310 [virtio_blk 19a65eeee9ae6fcf02edfad39bb9ddee07dcdaff] blk_mq_flush_plug_list.part.0+0x780/0x860 __blk_flush_plug+0x1ba/0x220 blk_finish_plug+0x3b/0x60 submit_initial_group_read+0x10a/0x290 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] flush_scrub_stripes+0x38e/0x430 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] scrub_stripe+0x82a/0xae0 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] scrub_chunk+0x178/0x200 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] scrub_enumerate_chunks+0x4bc/0xa30 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] btrfs_scrub_dev+0x398/0x810 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] btrfs_ioctl+0x4b9/0x3020 [btrfs e57987a360bed82fe8756dcd3e0de5406ccfe965] __x64_sys_ioctl+0xbd/0x100 do_syscall_64+0x5d/0xe0 entry_SYSCALL_64_after_hwframe+0x63/0x6b RIP: 0033:0x7f47e5e0952b - Crash, mostly due to above use-after-free [CAUSE] The converted fs has the following data chunk layout: item 2 key (FIRST_CHUNK_TREE CHUNK_ITEM 2214658048) itemoff 16025 itemsize 80 length 86016 owner 2 stripe_len 65536 type DATA|single For above logical bytenr 2214744064, it's at the chunk end (2214658048 + 86016 = 2214744064). This means btrfs_submit_bio() would split the bio, and trigger endio function for both of the two halves. However scrub_submit_initial_read() would only expect the endio function to be called once, not any more. This means the first endio function would already free the bbio::bio, leaving the bvec freed, thus the 2nd endio call would lead to use-after-free. [FIX] - Make sure scrub_read_endio() only updates bits in its range Since we may read less than 64K at the end of the chunk, we should not touch the bits beyond chunk boundary. - Make sure scrub_submit_initial_read() only to read the chunk range This is done by calculating the real number of sectors we need to read, and add sector-by-sector to the bio. Thankfully the scrub read repair path won't need extra fixes: - scrub_stripe_submit_repair_read() With above fixes, we won't update error bit for range beyond chunk, thus scrub_stripe_submit_repair_read() should never submit any read beyond the chunk.
来源:美国国家漏洞数据库 NVD
CVSS信息
N/A
来源:美国国家漏洞数据库 NVD
漏洞类别
N/A
来源:美国国家漏洞数据库 NVD
漏洞标题
Linux kernel安全漏洞
来源:中国国家信息安全漏洞库 CNNVD
漏洞描述信息
Linux kernel是美国Linux基金会的开源操作系统Linux所使用的内核。 Linux kernel存在安全漏洞,该漏洞源于在 ext4 转换 btrfs 时,scrub 会导致不可修复的故障。
来源:中国国家信息安全漏洞库 CNNVD
CVSS信息
N/A
来源:中国国家信息安全漏洞库 CNNVD
漏洞类别
其他
来源:中国国家信息安全漏洞库 CNNVD
二、漏洞 CVE-2024-26616 的公开POC
# POC 描述 源链接 神龙链接
三、漏洞 CVE-2024-26616 的情报信息